Difference between revisions 34832353 and 35044743 on enwiki{{background|derivative}} ===Example 1=== Consider ''f''(''x'') = 5: : <math>f'(x)=\lim_{h\rightarrow 0} \frac{f(x+h)-f(x)}{h} = \lim_{h\rightarrow 0} \frac{5-5}{h} = 0</math> The derivative of a [[constant function]] is [[0 (number)|zero]]. (contracted; show full)|- | |<math> = \lim_{h\rightarrow 0}(2x + h) = 2x </math> |} For any point ''x'', the slope of the function <math>f(x)=x^2</math> is <math>f'(x)=2x</math>. <math>Insert formula here</math> == Headline text == '''Bold text''' ----⏎ ===Example 4=== Consider ''f''(''x'') = √''x'': :{| |- |<math> f'(x)\, </math> |<math>= \lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h} </math> |- |j jfdirkp[jdi] |<math> = \lim_{h\rightarrow 0}\frac{\sqrt{x+h} - \sqrt{x}}{h} </math> |- | |<math> = \lim_{h\rightarrow 0}\frac{(\sqrt{x+h} - \sqrt{x})(\sqrt{x+h} + \sqrt{x})}{h(\sqrt{x+h} + \sqrt{x})} </math> |- | |<math> = \lim_{h\rightarrow 0}\frac{x+h - x}{h(\sqrt{x+h} + \sqrt{x})} </math> (contracted; show full)|- | |<math> = \frac{-1}{4 x \sqrt{x}}</math> |} [[Category:calculus]] [[Category:Mathematical notation]] [[fr:Exemples de calcul de dérivée]] All content in the above text box is licensed under the Creative Commons Attribution-ShareAlike license Version 4 and was originally sourced from https://en.wikipedia.org/w/index.php?diff=prev&oldid=35044743.
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