Difference between revisions 573276532 and 573276624 on enwikiIn [[modular arithmetic]], the '''method of successive substitution''' is a method of solving problems of [[simultaneous congruences]] by using the definition of the congruence equation. It is commonly applied in cases where the conditions of the [[Chinese remainder theorem]] are not satisfied. There is also an unrelated numerical-analysis method of successive substitution, a [[randomized algorithm]] used for [[root finding]], an application of [[fixed-point iteration]]. (contracted; show full) * x ≡ 4 (mod 11), the above method would prove to be inefficient. The only equality identity that we need is a ≡ b (mod m) is equivalent to a = m'''''k''''' + b, for every '''''k''''' belonging to the '''''set of integers'''''. == ='''PROCEDURE'''=== 1. Begin by rewriting the first congruence as '''''x = 2a + 1''''', where ''a belongs to the set of integers''. 2. Substitute the expression '''''2a + 1''''' for x in the next congruence to have '''''2a + 1 ≡ 2(mod 3)'''''. 3. Rewrite 2(mod 3) as '''''3a + 2 '''''and solve for a: (contracted; show full)* [[simultaneous equations]] [[Category:Modular arithmetic]] http://en.wikibooks.org/wiki/Discrete_Mathematics/Modular_arithmetic [[Category:Back Substitution]] [[Category:Modular Arithmetic]] [[Category:Modular Congruences]] All content in the above text box is licensed under the Creative Commons Attribution-ShareAlike license Version 4 and was originally sourced from https://en.wikipedia.org/w/index.php?diff=prev&oldid=573276624.
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