Difference between revisions 970125623 and 993195146 on enwiki{{DISPLAYTITLE:Shifting ''n''th root algorithm}} {{unreferenced|date=May 2010}} The '''shifting ''n''th root algorithm''' is an [[algorithm]] for extracting the [[nth root|''n''th root]] of a positive [[real number]] which proceeds iteratively by shifting in ''n'' [[numerical digit|digits]] of the radicand, starting with the most significant, and produces one digit of the root on each iteration, in (contracted; show full) _ 3/ 5. 000 000 000 000 000 \/ 1 = 300×(0^2)×1+30×0×(1^2)+1^3 - 4 000 3 913 = 300×(1^2)×7+30×1×(7^2)+7^3 ----- 87 000 0 = 300×(17^2 )*×0+30×17×(0^2)+0^3 ------- 87 000 000 78 443 829 = 300×(170^2)×9+30×170×(9^2)+9^3 ---------- 8 556 171 000 7 889 992 299 = 300×(1709^2)×9+30×1709×(9^2)+9^3 ------------- 666 178 701 000 614 014 317 973 = 300×(17099^2)×7+30×17099×(7^2)+7^3 --------------- 52 164 383 027 ===Fourth root of 7=== 1. 6 2 6 5 7 --------------------------- _ 4/ 7.0000 0000 0000 0000 0000 \/ 1 = 4000×(0^3)×1+600×(0^2)×(1^2)+40×0×(1^3)+1^4 - 6 0000 5 5536 = 4000×(1^3)×6+600×(1^2)×(6^2)+40×1×(6^3)+6^4 ------ 4464 0000 3338 7536 = 4000×(16^3)×2+600*(16^2)×(2^2)+40×16×(2^3)+2^4 --------- 1125 2464 0000 1026 0494 3376 = 4000×(162^3)×6+600×(162^2)×(6^2)+40×162×(6^3)+6^4 -------------- 99 1969 6624 0000 86 0185 1379 0625 = 4000×(1626^3)×5+600×(1626^2)×(5^2)+ ----------------- 40×1626×(5^3)+5^4 13 1784 5244 9375 0000 12 0489 2414 6927 3201 = 4000×(16265^3)×7+600×(16265^2)×(7^2)+ ---------------------- 40×16265×(7^3)+7^4 1 1295 2830 2447 6799 ==See also== * [[Methods of computing square roots]] * [[nth root algorithm|''n''th root algorithm]] ==External links== *[http://www.homeschoolmath.net/teaching/sqr-algorithm-why-works.php Why the square root algorithm works] "Home School Math". Also related pages giving examples of the long-division-like pencil and paper method for square roots. [[Category:Root-finding algorithms]] [[Category:Computer arithmetic algorithms]] [[Category:Digit-by-digit algorithms]] All content in the above text box is licensed under the Creative Commons Attribution-ShareAlike license Version 4 and was originally sourced from https://en.wikipedia.org/w/index.php?diff=prev&oldid=993195146.
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